54r^2=24

Solution for 54r^2=24 equation:

54r^2=24

We move all terms to the left:

54r^2-(24)=0

a = 54; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·54·(-24)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*54}=\frac{-72}{108}
=-2/3
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*54}=\frac{72}{108}
=2/3
$